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-x^2+6x+475=0
We add all the numbers together, and all the variables
-1x^2+6x+475=0
a = -1; b = 6; c = +475;
Δ = b2-4ac
Δ = 62-4·(-1)·475
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-44}{2*-1}=\frac{-50}{-2} =+25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+44}{2*-1}=\frac{38}{-2} =-19 $
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